QCE Chemistry - Unit 4 - Properties and structure of organic materials
Structure of Organic Compounds | QCE Chemistry
Revise homologous series, functional groups, naming and structural representations for QCE Chemistry organic compounds.
Updated 2026-05-17 - 5 min read
QCAA official coverage - Chemistry 2025 v1.3
Exact syllabus points covered
- Identify organic molecules including alkanes, alkenes, alkynes, alcohols, aldehydes, ketones, carboxylic acids, haloalkanes, esters, amines and amides.
- Discriminate between class and functional groups, e.g. for OH, hydroxyl is the functional group and alcohol is the class.
- Describe the features of a homologous series.
- Discriminate between saturated and unsaturated organic molecules.
- Discriminate between empirical, molecular and structural formulas.
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for alkanes, alkenes and alkynes
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for alcohols (primary, secondary and tertiary)
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for aldehydes and ketones
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for carboxylic acids
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for amines and amides
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for haloalkanes (primary, secondary and tertiary)
- Determine molecular and structural formulas for organic compounds, up to C10, including simple methyl and ethyl branched chains, for esters.
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for alkanes, alkenes and alkynes
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for alcohols (primary, secondary and tertiary)
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for aldehydes and ketones
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for carboxylic acids
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for haloalkanes (primary, secondary and tertiary)
- Apply IUPAC rules in the nomenclature of organic compounds, up to C10, including simple methyl and ethyl branched chains, for esters.
- Identify structural and stereoisomers, including geometrical (cis and trans) and optical isomers.
- Deduce the structural formula of geometrical (cis and trans) isomers (non-cyclic alkenes), optical isomers and isomers of the non-cyclic alkanes up to C6.
- Sketch the structural formula and apply IUPAC rules in the nomenclature for isomers of alkanes (non-cyclic) and alkenes (straight chain) up to C6, and for the geometrical (cis and trans) isomers of simple alkenes (non-cyclic).
- Determine the structural formula of optical isomers for simple organic compounds.
- Identify chiral carbon atoms.
- Analyse data to determine the structural, molecular and empirical formula of organic compound and the percentage composition of elements in organic compounds.
Organic chemistry can feel like a new language at first, but most of it comes down to two questions:
- What carbon skeleton does the molecule have?
- What functional group is attached to it?
The carbon skeleton tells you the size and shape of the molecule. The functional group tells you the part that usually controls reactivity, polarity, naming priority and many physical properties.
Original Sylligence diagram for organic functional groups.
Carbon skeletons and homologous series
A hydrocarbon contains only carbon and hydrogen. The main hydrocarbon families are:
| Family | General feature | Example | | --- | --- | --- | | Alkane | only single carbon-carbon bonds | ethane, $\mathrm{CH_3CH_3}$ | | Alkene | at least one carbon-carbon double bond | ethene, $\mathrm{CH_2=CH_2}$ | | Alkyne | at least one carbon-carbon triple bond | ethyne, $\mathrm{HCCH}$ | | Aromatic compound | benzene ring or related aromatic system | benzene, methylbenzene |
A homologous series is a family of compounds with the same functional group and similar chemical reactions. Consecutive members usually differ by $\mathrm{CH_2}$. For example, methane, ethane, propane and butane are all alkanes.
This matters because you can often predict trends. As the carbon chain grows, boiling point usually increases. As the same functional group appears in different molecules, similar reaction patterns appear.
Functional groups
Common QCE functional groups include:
| Functional group | Pattern to recognise | Example name | | --- | --- | --- | | Alkene | $\mathrm{C=C}$ | propene | | Haloalkane | $\mathrm{C-X}$, where $\mathrm{X}$ is F, Cl, Br or I | 1-bromopropane | | Alcohol | $\mathrm{-OH}$ on a carbon chain | propan-1-ol | | Aldehyde | terminal $\mathrm{-CHO}$ | propanal | | Ketone | internal $\mathrm{C=O}$ | propanone | | Carboxylic acid | $\mathrm{-COOH}$ | propanoic acid | | Ester | $\mathrm{-COO^-}$ between two carbon groups | ethyl ethanoate | | Amine | $\mathrm{-NH_2}$, $\mathrm{-NHR}$ or $\mathrm{-NR_2}$ | ethylamine | | Amide | $\mathrm{-CONH_2}$, $\mathrm{-CONHR}$ or $\mathrm{-CONR_2}$ | ethanamide |
Start by identifying the highest-priority functional group. For many school-level naming questions, the suffix gives this away: $\mathrm{-ol}$, $\mathrm{-al}$, $\mathrm{-one}$, $\mathrm{-oic\ acid}$, $\mathrm{-oate}$, $\mathrm{-amine}$ or $\mathrm{-amide}$.
Representations
The same molecule can be represented in several ways:
| Representation | What it shows well | Example for propan-1-ol | | --- | --- | --- | | Molecular formula | total numbers of each atom | $\mathrm{C_3H_8O}$ | | Structural formula | atoms and bonds clearly | $\mathrm{CH_3-CH_2-CH_2-OH}$ | | Condensed structural formula | structure in compact text form | $\mathrm{CH_3CH_2CH_2OH}$ | | Skeletal formula | carbon framework efficiently | line-angle drawing |
In a skeletal formula:
- every line end and vertex is a carbon atom unless another atom is written
- hydrogens attached to carbon are not usually shown
- hydrogens attached to heteroatoms, such as $\mathrm{O-H}$ or $\mathrm{N-H}$, are usually shown
- multiple bonds are drawn explicitly
For example, a three-carbon zigzag with $\mathrm{OH}$ at the end represents propan-1-ol, not ethanol. The line has two ends and one bend, so it has three carbon atoms.
Naming organic compounds
A reliable naming method is:
- Find the highest-priority functional group.
- Choose the longest carbon chain containing that group where required.
- Number the chain so the main functional group gets the lowest possible number.
- Name substituents, such as methyl, ethyl, fluoro, chloro, bromo or iodo.
- Put the name together with position numbers.
For example, $\mathrm{CH_3CH(OH)CH_2CH_3}$ is butan-2-ol. The parent chain has four carbons, so it is based on butane. The $\mathrm{-OH}$ group is on carbon 2, so the suffix becomes $\mathrm{-2-ol}$.
Isomers
Isomers have the same molecular formula but different arrangements of atoms.
Structural isomers have different connectivity. For example, $\mathrm{C_3H_8O}$ can be propan-1-ol, propan-2-ol or methoxyethane. Same formula, different bonding pattern.
Stereoisomers have the same connectivity but different three-dimensional arrangement. In QCE Chemistry, you may meet geometric isomers around a restricted bond, such as a carbon-carbon double bond, where rotation is not free.
How to describe structure in exam answers
When explaining a structure, avoid vague phrases like "it has oxygen" or "it is organic". Be specific:
- "The molecule contains a carboxylic acid functional group, $\mathrm{-COOH}$."
- "It is a secondary alcohol because the carbon bonded to $\mathrm{-OH}$ is attached to two other carbon atoms."
- "The molecule has a carbon-carbon double bond, so it is unsaturated."
These sentences give the marker chemical evidence, not just labels.
Quick check
Exam traps worth knowing
- Counting carbons incorrectly in skeletal formulas.
- Naming the longest chain before checking the highest-priority functional group.
- Treating molecules with the same formula as identical without checking structure.
- Forgetting that the carbon in $\mathrm{-CHO}$, $\mathrm{-COOH}$, $\mathrm{-COO^-}$ or $\mathrm{-CONH_2}$ is part of the parent chain when naming many compounds.